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Postgraduate level — Computer Science

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quiz Questions

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Q171

An electronics engineer uses a 4-variable Karnaugh Map (K-Map) to simplify a Boolean expression. If the minterms are located at positions m(0, 1, 2, 3, 5, 7, 8, 9, 10, 11), what is the minimum number of prime implicants (groups of sizes 8 or 4) required to cleanly cover all the 1s?

1 · 2 marks · MCQ

A.

1

B.

2

C.

3

D.

4

Explanation

Plotting on a 4-variable K-map shows that rows 0 and 2 combine with all columns to form an octet of size 8 covering m(0,1,2,3,8,9,10,11). The remaining minterms m(5,7) combine with m(1,3) to form a quad of size 4. Thus, exactly 2 prime implicants (one octet and one quad) cover the entire map layout.

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Q172

A digital circuit processes data using the 4-bit binary sequence 1101. What is the exact configuration profile when this value is cleanly converted into Gray Code?

1 · 2 marks · MCQ

A.

1111

B.

1011

C.

1001

D.

1110

Explanation

To convert Binary (B₃B₂B₁B₀) to Gray (G₃G₂G₁G₀): Keep the MSB: G₃ = B₃ = 1. Then XOR adjacent bits: G₂ = B₃ ⊕ B₂ = 1 ⊕ 1 = 0. G₁ = B₂ ⊕ B₁ = 1 ⊕ 0 = 1. G₀ = B₁ ⊕ B₀ = 0 ⊕ 1 = 1. The result is 1011.

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Q173

Which logic gate combination layout functions natively as a 'Universal Gate', capable of synthesizing any alternate Boolean algebra execution matrix exclusively on its own?

1 · 2 marks · MCQ

A.

AND and OR gates layout

B.

NAND and NOR gates matrix

C.

XOR and XNOR logic clusters

D.

Buffer and Inverter pipeline arrays

Explanation

NAND and NOR gates are classified structurally as universal logic gates because any foundational logic function (AND, OR, NOT) can be entirely built utilizing clusters of only that specific gate type.

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Q174

An internal CPU memory subsystem executes with a cache hit rate of exactly 85%. The cache memory speed is 4 nanoseconds (ns), while tracking misses require fetching data from main memory, which exhibits a latency of 40 nanoseconds (ns). What is the exact Effective Memory Access Time (EMAT) calculated for this processing layout?

1 · 2 marks · MCQ

A.

5.6 nanoseconds

B.

9.4 nanoseconds

C.

11.2 nanoseconds

D.

34.0 nanoseconds

Explanation

EMAT Formula = (Hit Rate × Cache Latency) + (Miss Rate × Main Memory Latency). Miss Rate = 1 - 0.85 = 0.15. Calculation: (0.85 × 4 ns) + (0.15 × 40 ns) = 3.4 ns + 6.0 ns = 9.4 nanoseconds.

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Q175

In high-level storage architectures, a system partition profile updates its data metrics allocation to exactly 2.5 Terabytes (TB). What is the mathematically equivalent size of this allocation when scaled directly in Gigabytes (GB) inside standard binary computing frameworks?

1 · 2 marks · MCQ

A.

2500 GB

B.

2560 GB

C.

2048 GB

D.

5120 GB

Explanation

In standardized binary computing scales, 1 Terabyte (TB) is equal to exactly 1024 Gigabytes (GB). Therefore, 2.5 TB × 1024 GB/TB = 2560 Gigabytes.

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Q176

An output function simplified using a 3-variable Karnaugh Map (K-Map) maps minterms at positions m(1, 3, 5, 7). Which core algebraic grouping configuration represents the most minimized Boolean expression output?

1 · 2 marks · MCQ

A.

X'Z + YZ

B.

Z

C.

X + Y'Z

D.

XYZ

Explanation

Mapping m(1, 3, 5, 7) on a 3-variable K-Map (variables X, Y, Z where X is the MSB) forms a single quad of size 4 across the columns where Z = 1. This completely eliminates X and Y parameters, minimizing cleanly to just 'Z'.

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Q177

A digital execution array tracks processing metrics via the 4-bit Binary Coded Decimal (BCD) standard layout. What is the mathematically equivalent binary stream configuration profile for the decimal number 79 when packed natively into BCD?

1 · 2 marks · MCQ

A.

0100 1111

B.

0111 1001

C.

1001 0111

D.

0011 1001

Explanation

The BCD architecture encodes each individual decimal digit independently into its direct 4-bit binary equivalent vector track. Decimal 7 maps cleanly to 0111, and decimal 9 maps cleanly to 1001. Combining them sequentially yields 0111 1001.

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Q178

Which fundamental basic computer peripheral device functions as a specialized non-impact vector output terminal designed natively to draw continuous complex engineering blueprints using autonomous plotting pens?

1 · 2 marks · MCQ

A.

Flatbed digitizer engine

B.

Plotter

C.

Dot Matrix striking head

D.

Laser photoreceptor drum

Explanation

A Plotter is a specialized vector-graphic output device that renders high-precision continuous line graphics, structural layouts, and engineering blueprints directly onto oversized paper layers using motorized ink pens, unlike standard raster pixel printing units.

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Q179

The integration of Ultra Large Scale Integration (ULSI) technology, consolidating tens of millions of transistor gates cleanly onto a single microprocessor chip, archaeologically defines which computing generation parameter natively?

1 · 2 marks · MCQ

A.

Third Generation layout tracking

B.

Fourth Generation micro grid

C.

Fifth Generation architecture phase

D.

Sixth Generation neural matrix

Explanation

The Fifth Generation of basic computing architectures is characteristically defined by the transition into ULSI chip layouts, mass multi-core parallel processing streams, and the formative baseline tracking frameworks of artificial intelligence architectures.

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Q180

A specialized computer storage channel exhibits an internal bus path layout width of exactly 64 bits. If the hardware execution clock updates at a frequency of 800 MHz, what is the maximum theoretical data transfer throughput speed achievable across this hardware setup?

1 · 2 marks · MCQ

A.

1600 MB/s

B.

3200 MB/s

C.

6400 MB/s

D.

12800 MB/s

Explanation

Throughput Calculation Steps: Convert Bus Width down into Bytes: 64 bits / 8 = 8 Bytes. Throughput = Bus Width (in Bytes) × Clock Frequency Speed = 8 Bytes × 800 MHz = 6400 MB/s. Converting via binary scaling layouts: 6400 / 1000 = exactly 6.4 GB/s (or 6400 MB/s).