Computer Science Topics
Postgraduate level — Computer Science
Choose question count and time — session stays in your browser only.
filter_alt Topics
Basic Computers
Algorithms
Data Structures
Operating Systems
DBMS
Computer Networks
quiz Questions
Q201
An output function simplified using a 4-variable Karnaugh Map (K-Map) maps minterms at positions m(0, 1, 4, 5). Which minimized algebraic expression represents the most optimal product term output?
W'Y'
X'Z'
WY'
W'X'
Explanation
Mapping m(0, 1, 4, 5) on a 4-variable K-Map (variables W, X, Y, Z where WX tracks the rows and YZ tracks the columns) fills the first two columns of the first two rows. This creates a contiguous quad of size 4. Across this group, rows change from 00 to 01 (W changes, X' remains constant) and columns change from 00 to 01 (Y' remains constant, Z changes). This completely eliminates W and Z variables, minimizing cleanly to W'Y'.
Q202
A digital circuit processes data using the 4-bit binary sequence 1001. What is the exact configuration profile when this value is cleanly converted into an 8-bit Extended Binary Coded Decimal Interchange Code (EBCDIC) zone-digit numeric layout?
0011 1001
1111 1001
1001 1111
1100 1001
Explanation
The binary sequence 1001 corresponds to the decimal number 9. In the classic IBM EBCDIC standard character encoding layout, numeric digits (0-9) are mapped natively with a fixed zone prefix configuration of '1111' (hexadecimal F) followed by the direct 4-bit binary digit representation. Therefore, decimal 9 (1001) maps cleanly to the 8-bit pattern 1111 1001.
Q203
An electronics engineer combines logic gates to construct an execution block whose Boolean algebraic properties reduce cleanly to Y = A ⊕ B. Which single logic gate configuration natively executes this exact mathematical function in a standalone component?
XNOR Gate
XOR Gate
NAND Gate
NOR Gate
Explanation
The mathematical operator symbol '⊕' explicitly represents the Boolean Exclusive OR (XOR) operation. An XOR gate characteristically produces a binary output state of '1' if and only if its input variables are complementary or unequal to each other.
Q204
An internal CPU memory access sequence runs with a cache hit efficiency index of exactly 92%. If the hardware cache speed latency is 2 nanoseconds (ns) and misses require jumping to the slower main memory which displays a latency of 50 nanoseconds (ns), what is the computed Effective Memory Access Time (EMAT) for this hardware loop?
3.84 nanoseconds
5.84 nanoseconds
6.16 nanoseconds
11.84 nanoseconds
Explanation
Formula for Effective Access Time tracking metrics: EMAT = (Hit Rate × Cache Latency) + (Miss Rate × Main Memory Latency). Given parameters: Hit Rate = 0.92, Miss Rate = 1 - 0.92 = 0.08. Calculation: (0.92 × 2 ns) + (0.08 × 50 ns) = 1.84 ns + 4.00 ns = exactly 5.84 nanoseconds.
Q205
If a processor architecture implements a 14-bit wide physical address bus layout natively, what is the absolute maximum memory capacity parameter (byte-addressable storage index limits) that this CPU can directly reference?
4 Kilobytes (KB)
8 Kilobytes (KB)
16 Kilobytes (KB)
32 Kilobytes (KB)
Explanation
The maximum direct reference capacity threshold is calculated mathematically as 2^n bytes, where n represents the bit width of the address bus line pipelines. Thus, 2^14 = 16,384 distinct byte locations. Converting via standard binary scaling indices: 16,384 / 1024 = exactly 16 Kilobytes (KB).
Q206
An output function simplified using a 4-variable Karnaugh Map (K-Map) maps minterms at positions m(2, 3, 10, 11). Which minimized product term represents the simplified Boolean expression output?
W'Y
X'Y
YZ'
X'Z
Explanation
Mapping m(2, 3, 10, 11) on a 4-variable K-Map (variables W, X, Y, Z where WX tracks the rows and YZ tracks the columns) fills the columns 11 and 10 of rows 00 and 10. This creates a contiguous quad of size 4. Across this group, row variables change from 00 to 10 (W changes, X' remains constant) and column variables remain constant at 11 and 10 (Y remains constant at 1, Z changes). This completely eliminates W and Z variables, minimizing cleanly to X'Y.
Q207
Which type of computer data encoding standard utilizes a 4-bit configuration mapping strategy where the numeric value of each decimal digit is offset by adding a constant factor of 3 before binary conversion?
Pure 8-4-2-1 BCD format
Excess-3 Code layout
Gray Code structure
EBCDIC cluster standard
Explanation
Excess-3 code is a non-weighted, self-complementing alternative binary-coded decimal code framework. It is calculated explicitly by adding decimal 3 (binary 0011) natively to each individual BCD digit string.
Q208
An output circuit expression simplified using Boolean logic theorems reduces down cleanly to the statement Y = (A • B)'. Which specific physical logic gate natively tracks this operational profile inside a single logic chip layout configuration component?
NOR Gate
NAND Gate
XOR Gate
XNOR Gate
Explanation
The Boolean algebraic expression Y = (A • B)' explicitly tracks the operation of a NAND gate. A NAND gate acts as an AND gate directly followed by an inverter state, characteristically generating a binary output '0' if and only if all its binary input lines are simultaneously set to '1'.
Q209
An internal CPU memory access sequence runs with a cache hit efficiency rate of exactly 88%. If the microchip cache speed latency is 3 nanoseconds (ns) and misses require jumping to the slower main memory which displays a latency of 40 nanoseconds (ns), what is the computed Effective Memory Access Time (EMAT) for this hardware loop?
4.44 nanoseconds
7.44 nanoseconds
8.56 nanoseconds
14.44 nanoseconds
Explanation
Formula for Effective Access Time tracking metrics: EMAT = (Hit Rate × Cache Latency) + (Miss Rate × Main Memory Latency). Given parameters: Hit Rate = 0.88, Miss Rate = 1 - 0.88 = 0.12. Calculation steps: (0.88 × 3 ns) + (0.12 × 40 ns) = 2.64 ns + 4.80 ns = exactly 7.44 nanoseconds.
Q210
If a processor architecture implements a 13-bit wide physical address bus layout natively, what is the absolute maximum memory capacity parameter (byte-addressable storage index limits) that this CPU can directly reference?
2 Kilobytes (KB)
4 Kilobytes (KB)
8 Kilobytes (KB)
16 Kilobytes (KB)
Explanation
The maximum direct reference capacity threshold is calculated mathematically as 2^n bytes, where n represents the bit width of the address bus line pipelines. Thus, 2^13 = 8192 distinct byte locations. Converting via standard binary scaling indices: 8192 / 1024 = exactly 8 Kilobytes (KB).